Sum of three fractions

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\(\frac{1}{6}+\frac{1}{8}+\frac{1}{9}=?\)
\(\frac{59}{72}\)
\(\frac{49}{72}\)
\(\frac{13}{24}\)
\(\frac{29}{72}\)
\(\frac{19}{72}\)

Calculator
Hint \(\frac{1}{6}+\frac{1}{8}+\frac{1}{9}\)
\(=\frac{1\times{12}}{6\times{12}}+\frac{1\times{9}}{8\times{9}}+\frac{1\times{8}}{9\times{8}}\)
\(=\frac{12}{72}+\frac{9}{72}+\frac{8}{72}\)
\(=\frac{12+9+8}{72}\)
\(=\frac{29}{72}\)
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